-2m^2+8m=-64

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Solution for -2m^2+8m=-64 equation:



-2m^2+8m=-64
We move all terms to the left:
-2m^2+8m-(-64)=0
We add all the numbers together, and all the variables
-2m^2+8m+64=0
a = -2; b = 8; c = +64;
Δ = b2-4ac
Δ = 82-4·(-2)·64
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*-2}=\frac{-32}{-4} =+8 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*-2}=\frac{16}{-4} =-4 $

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